A cistern of capacity 8000 litres measures externally 3.3 m by 2.6 m by 1.1 m and its walls are 5 cm thick. The thickness of the bottom is:
90 cm
1 dm
1 m
1.1 cm
Explanation:
Let the thickness of the bottom be x cm.
Then, [(330 - 10) x (260 - 10) x (110 - x)] = 8000 x 1000
=> 320 x 250 x (110 - x) = 8000 x 1000
=> (110 - x) = $\dfrac{8000 \times 1000}{320 \times 250} = 100$
=> x = 10 cm = 1 dm.
Let the thickness of the bottom be x cm.
Then, [(330 - 10) x (260 - 10) x (110 - x)] = 8000 x 1000
=> 320 x 250 x (110 - x) = 8000 x 1000
=> (110 - x) = $\dfrac{8000 \times 1000}{320 \times 250} = 100$
=> x = 10 cm = 1 dm.