50 men took a dip in a water tank 40 m long and 20 m broad on a religious day. If the average displacement of water by a man is $4 m^3$, then the rise in the water level in the tank will be:
20 cm
25 cm
35 cm
50 cm
Explanation:
Total volume of water displaced = (4 x 50) $m^3 = 200 m^3.$
ஃ Rise in water level =$( \dfrac{200}{40 \times 20})$m 0.25 m = 25cm.
Total volume of water displaced = (4 x 50) $m^3 = 200 m^3.$
ஃ Rise in water level =$( \dfrac{200}{40 \times 20})$m 0.25 m = 25cm.