The slant height of a right circular cone is 10 m and its height is 8 m. Find the area of its curved surface.
$30 \pi m^2$
$40 \pi m^2$
$60 \pi m^2$
$80 \pi m^2$
Explanation:
l = 10 m,
h = 8 m.
So, $r = \sqrt{l^2 - h^2} = \sqrt{(10)^2 - (8)^2} = 6m$
ஃ Curved surface area =$ \pi rl = (\pi \times 6 \times 10) m^2 = 60 \pi m^2.$
l = 10 m,
h = 8 m.
So, $r = \sqrt{l^2 - h^2} = \sqrt{(10)^2 - (8)^2} = 6m$
ஃ Curved surface area =$ \pi rl = (\pi \times 6 \times 10) m^2 = 60 \pi m^2.$