In a bag, there are coins of 25 p, 10 p and 5 p in the ratio of 1 : 2 : 3. If there is Rs. 30 in all, how many 5 p coins are there?
50
100
150
200
Explanation:
Let the number of 25 p, 10 p and 5 p coins be x, 2x, 3x respectively.
Then, sum of their values = Rs.$(\dfrac{25x}{100} + \dfrac{10 \times2x}{100} + \dfrac{5 \times3x}{100}) = Rs.\dfrac{60x}{100}$
ஃ $\dfrac{60x}{100} = 30 $<=> x = $\dfrac{30 \times100}{60} = 50.$
Hence, the number of 5 p coins = (3 x 50) = 150.
Let the number of 25 p, 10 p and 5 p coins be x, 2x, 3x respectively.
Then, sum of their values = Rs.$(\dfrac{25x}{100} + \dfrac{10 \times2x}{100} + \dfrac{5 \times3x}{100}) = Rs.\dfrac{60x}{100}$
ஃ $\dfrac{60x}{100} = 30 $<=> x = $\dfrac{30 \times100}{60} = 50.$
Hence, the number of 5 p coins = (3 x 50) = 150.