Find the angle of elevation of the sun when the shadow of a pole of 18 m height is 6√3m long?
30°
60°
45°
None of these
Explanation:
Let RQ be the pole and PQ be the shadow
Given that RQ = 18 m and PQ =6√3 m
Let the angle of elevation, $\angle$RPQ = θ
From the right $\triangle$ PQR,
tanθ=$\dfrac{RQ}{PQ}=\dfrac{18}{6\sqrt{3}}=\dfrac{3}{\sqrt{3}}$=√3
⇒θ=tan−1(√3)=60°
Let RQ be the pole and PQ be the shadow
Given that RQ = 18 m and PQ =6√3 m
Let the angle of elevation, $\angle$RPQ = θ
From the right $\triangle$ PQR,
tanθ=$\dfrac{RQ}{PQ}=\dfrac{18}{6\sqrt{3}}=\dfrac{3}{\sqrt{3}}$=√3
⇒θ=tan−1(√3)=60°