Rajat makes 8 open cones of height 24 cm and slant height 25 cm from a sheet of thick paper. Find the area of the sheet.
550 sq. m.
4400 sq. m.
6000 sq. m.
6236 sq.m.
Explanation:
L2 = r2 + h2 = 252 - 242
∴ r = 7 cm
Curved surface area of cone = 3.142 x 7 x 25 = 550 sq.m.
Since the cone is open, it means, it just has curved surface.One sheet can make 8 cones.
So area of one sheet = Curved surface area of 8 cones = 8 x 550
∴ Area of one sheet = 4400 sq.cm.
L2 = r2 + h2 = 252 - 242
∴ r = 7 cm
Curved surface area of cone = 3.142 x 7 x 25 = 550 sq.m.
Since the cone is open, it means, it just has curved surface.One sheet can make 8 cones.
So area of one sheet = Curved surface area of 8 cones = 8 x 550
∴ Area of one sheet = 4400 sq.cm.