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Weight of A and B are in the ratio of 3:5. If the weight of A is increased by 20 percent and then the total weight becomes 132 kg
with an increase of 10 percent. B weight is increased by what percent.

2%
3%
4%
5%
E) None of these
Explanation:

Weight of A and B are 3x and 5x.

Initial weight before increase = $\dfrac{132 \times 100)}{110}$ = 120

8x = 120. X = 15

Initial weight of A and B are 45 and 75 kg respectively.

New weight of A = 54 so weight of B = 132 – 54 = 78.

So % increase = $[\dfrac{78-75}{75}] \times 100$ = 4 %
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