If N>1000, what could be the least value of N?
1249
1023
1202
1246
Explanation:
Suppose N=5x+1
A took (x+1) biscuit.
Now 4x is of the form 5y+1 then x must be in the form 5z+4
⇒4(5z+4)=5y+1
⇒y=4z+3 and x=5z+4
The ratio of number of biscuits that A and B took is
[(5z+4)+1]:[(4z+3)+1]=5:4
So, we can say that any two successive persons A, B, C and D take coins in the ratio of 5:4
Let the number of biscuits that A, B, C and D took be a, b, c and d respectively.
a:b=b:c=c:d=5:4
a:b:c:d=125:100:80:64
⇒a=125k
⇒x=125k−1 and N=5x+1=625k−4
As, N>1000, the least value of N is when k=2
⇒N= 1246
Suppose N=5x+1
A took (x+1) biscuit.
Now 4x is of the form 5y+1 then x must be in the form 5z+4
⇒4(5z+4)=5y+1
⇒y=4z+3 and x=5z+4
The ratio of number of biscuits that A and B took is
[(5z+4)+1]:[(4z+3)+1]=5:4
So, we can say that any two successive persons A, B, C and D take coins in the ratio of 5:4
Let the number of biscuits that A, B, C and D took be a, b, c and d respectively.
a:b=b:c=c:d=5:4
a:b:c:d=125:100:80:64
⇒a=125k
⇒x=125k−1 and N=5x+1=625k−4
As, N>1000, the least value of N is when k=2
⇒N= 1246