In a pocket of A, the ratio of Rs.1 coins, 50p coins and 25p coins can be expressed by three consecutive odd prime numbers that are in ascending order. The total value of coins in the bag is Rs 58. If the number of Rs.1, 50p, 25p coins are reversed, find the new total value of coins in the pocket of A?
Rs 68
Rs 43
Rs 75
Rs 82
Explanation:
Since the ratio of the number of Rs. 1, 50p and 25p coins can be represented by 3 consecutive odd numbers that are prime in ascending order, the only possibility for the ratio is 3:5:7.
Let the number of Re1, 50p and 25p coins be 3k,5k and 7k respectively.
Hence, total value of coins in paise
⇒100×3k+50×5k+25×7k
=725k
=5800
⇒k=8.
If the number of coins of Rs. 1,50p and 25p is reversed, the total value of coins in the Bag (in paise)
=100×7k+50×5k+25×3k=1025k (In above we find the value of k).
⇒8200p=Rs. 82.
Since the ratio of the number of Rs. 1, 50p and 25p coins can be represented by 3 consecutive odd numbers that are prime in ascending order, the only possibility for the ratio is 3:5:7.
Let the number of Re1, 50p and 25p coins be 3k,5k and 7k respectively.
Hence, total value of coins in paise
⇒100×3k+50×5k+25×7k
=725k
=5800
⇒k=8.
If the number of coins of Rs. 1,50p and 25p is reversed, the total value of coins in the Bag (in paise)
=100×7k+50×5k+25×3k=1025k (In above we find the value of k).
⇒8200p=Rs. 82.