Exponential form: $b^{y}$ = x

Logarithm form: $log_{b} (x)$ = y

Given: $log_{2} 64$

Let the solution of $log_{2} 64$ be y.

$Log_{2} 64$ = y

$2^{y}$ = 64

$2^{6}$ = 64

Therefore, y = 6