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At what temperature will the rms speed of oxygen molecules become just sufficient for escaping from the Earths atmosphere?
(Given : Mass of oxygen molecule (m) = 2.76 × 10^{-26}kg
Boltzmanns constant $k_{B} = 1.38 × 10^{-23} JK^{-1})$

5.016 × $10^{4} K$
8.360 × $10^{4} K$
2.508 × $10^{4} K$
1.254 × $10^{4} K$
Explanation:

$V_{escape}$ = 11200 m/s
Say at temperature T it attains $V_{escape}$
So, $\sqrt{\dfrac{3K_{B}T}{m_{O_{2}}}}=11200m/s$
On solving,
T= 8.360 * $10^{4}K$

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