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Among $CaH_2, BeH_2 , BaH_2,$ the order of ionic character is

$BeH_2 < BaH_2 < CaH_2$
$CaH_2 < BeH_2 < BaH_2$
$BeH_2 < CaH_2 < BaH_2$
$BaH_2 < BeH_2 < CaH_ 2$
Explanation:

For $2^{nd}$ group hydrides, on moving down the group metallic character of metals increases so ionic character of metal hydride increases. Hence the option (3) should be correct option.
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