Question: What will be the total weight of 10 poles, each of the same weight ?
Statements:
One-fourth of the weight of each pole is 5 kg.
The total weight of three poles is 20 kilograms more than the total weight of two poles.
I alone is sufficient while II alone is not sufficient
II alone is sufficient while I alone is not sufficient
Either I or II is sufficient
Neither I nor II is sufficient
Explanation:
From I, we conclude that weight of each pole = (4×5) kg = 20 kg.So, total weight of 10 poles = (20 x 10) kg = 200 kg.From II, we conclude that:Weight of each pole = (weight of 3 poles) – (weight of 2 poles) = 20 kg.So, total weight of 10 pojes = (20 x 10) kg = 200 kg.
From I, we conclude that weight of each pole = (4×5) kg = 20 kg.So, total weight of 10 poles = (20 x 10) kg = 200 kg.From II, we conclude that:Weight of each pole = (weight of 3 poles) – (weight of 2 poles) = 20 kg.So, total weight of 10 pojes = (20 x 10) kg = 200 kg.