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Aptitude Area Practice Q&A-Easy Page: 10
8253.Find the area of a rectangle whose length is 15 cm and breadth is 50 mm.
75cm2
85cm2
70cm2
80cm2
Explanation:

Length (l) = 15 cm.

10 mm = 1 cm.

Therefore, 50 mm = 50/10 cm = 5 cm.

Breadth = 5 cm.

Area = l × b

= 15 × 5 sq. cm.

= 75cm2.

If D = 20 cm, calculate the area of circle?.
Solution:

Since r is half the diameter, r = 20 divided by 2

r = 10 cm

A = $\pi$ × r2 = 3.14 × 102 = 3.14 × 100 = 314 cm2

8255.Sam cuts grass at Rs.0.10 per square meter.How much does Sam earn cutting this area?
Rs.54
Rs.56
Rs.57
Rs.58
Explanation:

area grass

Lets break the area into two parts:

Part A is a square:

Area of A = a2 = 20m × 20m = 400m2

Part B is a triangle. Viewed sideways it has a base of 20m and a height of 14m.

Area of B =$\dfrac{1}{2}\left(b \times h \right)$ = $\dfrac{1}{2}\left(20 \times 14 \right)$ = 140m2

So the total area is:

Area = Area of A + Area of B = 400m2 + 140m2 = 540m2

Sam earns Rs.0.10 per square meter

Sam earns = Rs.0.10 × 540m2 = Rs.54

8256.A parallelogram has a base of 12 cm and a side length of 6 cm, what is its Perimeter?
40cm
38cm
36cm
42cm
Explanation:

The Perimeter is 2 times the (base + side length)

Perimeter = 2(b+s)

Perimeter = 2 × (12 cm + 6 cm) = 2 × 18 cm = 36cm

10898.The area of a triangle is with base 4m and height 5m?
20 sq m
10 sq m
5 sq m
3 sq m
Explanation:

1/2 $\times$ 4 $\times$ 5 =10$m^2$

10899.The area of a triangle will be when a = 1m, b = 2m, c = 3m, a, b, c being lengths of respective sides.
0 sq m
3 sq m
2 sq m
6 sq m
Explanation:

S = (1 + 2 + 3)/2 = 3

=> No triangle exists

10900.The length of each side of an equilateral triangle having an area of 4$\sqrt{3}$ cm2 is?
4/3 cm
3/4 cm
3 cm
4 cm
Explanation:

$\dfrac{\sqrt{3}}{4}a^2 = 4\sqrt{3} => a = 4$

10901.The altitude of an equilateral triangle of side 2$\sqrt{3}$ cm is?
3/2 cm
1/2 cm
3/4 cm
3 cm
Explanation:

$3\sqrt{2} \times 2\sqrt{3}$ = 3cm

10902.The base of a right triangle is 8 and hypotenuse is 10. Its area is?
12
80
59
24
Explanation:

$h^2= 10^2-8^2 = 6^2\rightarrow h=6$

$\dfrac{1}{2}\times8\times6 = 24$

10903.The sides of a triangle are in the ratio 5: 12: 13 and its perimeter is 300 m, its area is?
3000 sq m
3127 sq m
3225 sq m
3750 sq m
Explanation:

5x + 12x + 13x = 300 => x = 10

a = 50, b = 120, c = 130

S = (50 + 120 + 130)/2 = 150

$\sqrt{150\times100\times30\times20}\rightarrow3000$

10904.What is the area of square field whose side of length 15 m?
225 sq m
220 sq m
100 sq m
30 sq m
Explanation:

$15 \times 15$ = 225 sq m

10905.What is the area of a square field whose diagonal of length 20 m?
300 sq m
250 sq m
200 sq m
400 sq m
Explanation:

$\dfrac{d^2}{2}$ = $\dfrac{\left(20\times20\right)}{2}$ = 200 sq m

10906.What is the perimeter of a square field whose diagonal is 8v2?
64 m
32 m
30 m
16 m
Explanation:

$a\sqrt{2}= 8\sqrt{2} \rightarrow a=8$

10907.The ratio of the area of a square to that of the square drawn on its diagonal is?
2:5
3:4
3:5
1:2
Explanation:

$a^2:\left(a\sqrt{2}\right)^2$

$a^2:2a^2 \rightarrow$ 1:2

10908.The perimeter of one square is 48 cm and that of another is 20 cm. Find the perimeter and the diagonal of a square which is equal in area to these two combined?
15$\sqrt{2}$ cm
13$\sqrt{2}$ cm
16$\sqrt{2}$ cm
17$\sqrt{2}$ cm
Explanation:

4a = 48

4a = 20

a = 12 a = 5

$a^2$ = 144 $a^2$ = 25

Combined area = $a^2$ = 169 => a = 13

d = 13$\sqrt{2}$

10909.If the perimeter of a rectangular garden is 600 m, its length when its breadth is 100 m is?
650 m
600 m
200 m
300 m
Explanation:

2(l + 100) = 600 => l = 200 m

10910.A rectangular field has area equal to 150 sq m and perimeter 50 m. Its length and breadth must be?
12 m, 10 m
13 m, 12 m
14 m, 11 m
15 m, 10 m
Explanation:

lb = 150

2(l + b) = 50 => l + b = 25

l - b = 5

l = 15 b = 10

10911.One side of a rectangular field is 4 m and its length along diagonal is 5 m. What is the area of the field?
12 sq m
4$\sqrt{14}$ sq m
20 sq m
15 sq m
Explanation:

5=$\sqrt{4^2+b^2}\rightarrow b^2 =9$

lb = 3 $\times$ 4 = 12

10912.A man walked 20 m to cross a rectangular field diagonally. If the length of the field is 16 cm. Find the breadth of the field is?
11 m
12 m
13 m
14 m
Explanation:

20=$\sqrt{16^2+b^2}\rightarrow$ b =12

10913.Sides of a rectangular park are in the ratio 3: 2 and its area is 3750 sq m, the cost of fencing it at 50 ps per meter is?
Rs.150
Rs.100
Rs.125
Rs.175
Explanation:

3x $\times$ 2x = 3750 => x = 25

2(75 + 50) = 250 m

250 $\times$ 1/2 = Rs.125

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