44048.The true discount on Rs. 1760 due after a certain time at 12% per annum is Rs. 160. The time after which it is due is:
6 months
8 months
9 months
10 months
Explanation:
P.W. = Rs. (1760 -160) = Rs. 1600.
S.I. on Rs. 1600 at 12% is Rs. 160.
Time=$[\dfrac{100 \times 160}{1600 \times 12}]=\dfrac{5}{6}years
=[\dfrac{5}{6} \times 12]$months=10 months
P.W. = Rs. (1760 -160) = Rs. 1600.
S.I. on Rs. 1600 at 12% is Rs. 160.
Time=$[\dfrac{100 \times 160}{1600 \times 12}]=\dfrac{5}{6}years
=[\dfrac{5}{6} \times 12]$months=10 months
44049.Goods were bought for Rs. 600 and sold the same for Rs. 688.50 at a credit of 9 months and thus gaining 2% The rate of interest per annum is:
16 $\dfrac{2}{3}%$
14$\dfrac{1}{2}%$
13$\dfrac{1}{3}%$
15%
Explanation:
S.P. = 102% of Rs. 600 =$(\dfrac{102}{100}\times 600)$=Rs.612
Now, P.W. = Rs. 612 and sum = Rs. 688.50.
T.D. = Rs. (688.50 - 612) = Rs. 76.50.
Thus, S.I. on Rs. 612 for 9 months is Rs. 76.50.
Rate=$[\dfrac{100 \times 76.50 }{612 \times \dfrac{3}{4}}]$%=16$\dfrac{2}{3}$%
S.P. = 102% of Rs. 600 =$(\dfrac{102}{100}\times 600)$=Rs.612
Now, P.W. = Rs. 612 and sum = Rs. 688.50.
T.D. = Rs. (688.50 - 612) = Rs. 76.50.
Thus, S.I. on Rs. 612 for 9 months is Rs. 76.50.
Rate=$[\dfrac{100 \times 76.50 }{612 \times \dfrac{3}{4}}]$%=16$\dfrac{2}{3}$%
44050.The interest on Rs. 750 for 2 years is the same as the true discount on Rs. 960 due 2 years hence. If the rate of interest is the same in both cases, it is:
12%
14%
15%
16$\dfrac{2}{3}%$ %
Explanation:
S.I. on Rs. 750 = T.D. on Rs. 960.
This means P.W. of Rs. 960 due 2 years hence is Rs. 750.
T.D. = Rs. (960 - 750) = Rs. 210.
Thus, S.I. on R.s 750 for 2 years is Rs. 210.
Rate=$[\dfrac{100 \times 210}{750 \times 2}]$%=14%
S.I. on Rs. 750 = T.D. on Rs. 960.
This means P.W. of Rs. 960 due 2 years hence is Rs. 750.
T.D. = Rs. (960 - 750) = Rs. 210.
Thus, S.I. on R.s 750 for 2 years is Rs. 210.
Rate=$[\dfrac{100 \times 210}{750 \times 2}]$%=14%
44056.A man buys a watch for Rs. 1950 in cash and sells it for Rs. 2200 at a credit of 1 year. If the rate of interest is 10% per annum, the man:
gains Rs. 55
gains Rs. 50
loses Rs. 30
gains Rs. 30
Explanation:
S.P.= P.W. of Rs. 2200 due 1 year hence
= Rs.$[\dfrac{2200\times 100}{100+(10\times 1)}]$
=Rs.2,000
Gain=Rs.(2000-1950)=Rs.50
S.P.= P.W. of Rs. 2200 due 1 year hence
= Rs.$[\dfrac{2200\times 100}{100+(10\times 1)}]$
=Rs.2,000
Gain=Rs.(2000-1950)=Rs.50
44057.The banker s discount on Rs 1600 at 6% is the same as the true discount on Rs 1624 for the same time and at the same rate .Find the interval of time between the date of discounting and the legally due date.
4 months
14 months
3 months
13 months
Explanation:
Let the interval of time be x years.
B.D=$\dfrac{1600 \times 6 \times x}{100}$
T.D=$\dfrac{1624 \times 6 \times x}{100+(6 \times x)}$
x=$\dfrac{1}{4}$years or 3months.
Let the interval of time be x years.
B.D=$\dfrac{1600 \times 6 \times x}{100}$
T.D=$\dfrac{1624 \times 6 \times x}{100+(6 \times x)}$
x=$\dfrac{1}{4}$years or 3months.
44059.If the true discount on s sum due 2 years hence at 14% per annum be Rs. 168, the sum due is:
Rs. 768
Rs. 968
Rs. 1960
Rs. 2400
Explanation:
P.W=$\dfrac{100\times T.D}{R\times T}=\dfrac{100 \times 168}{14 \times 2}=600$
sum=(P.D+T.D)=Rs.(600+168)=Rs.768.
P.W=$\dfrac{100\times T.D}{R\times T}=\dfrac{100 \times 168}{14 \times 2}=600$
sum=(P.D+T.D)=Rs.(600+168)=Rs.768.
44062.The true discount on Rs. 2562 due 4 months hence is Rs. 122. The rate percent is:
12%
13%
15%
14%
Explanation:
P.W=Rs.(2562-122)=Rs.2440
S.I on Rs.2440 for 4 months is Rs.122
Rate=$[\dfrac{100 \times 122}{2440 \times \dfrac{1}{3}}]$%
P.W=Rs.(2562-122)=Rs.2440
S.I on Rs.2440 for 4 months is Rs.122
Rate=$[\dfrac{100 \times 122}{2440 \times \dfrac{1}{3}}]$%
44063.The true discount on a bill due 9 months hence at 16% per annum is Rs. 189. The amount of the bill is:
Rs. 1386
Rs. 1764
Rs. 1575
Rs. 2268
Explanation:
Let P.W. be Rs. x.
Then, S.I. on Rs. x at 16% for 9 months = Rs. 189.
X $ \times 16 \times \dfrac{9}{12} \times \dfrac{1}{100}=189 or x=1575$
P.W=Rs.1575
Sum of due =P.W +T.D =Rs.(1575+189)=Rs.1764
Let P.W. be Rs. x.
Then, S.I. on Rs. x at 16% for 9 months = Rs. 189.
X $ \times 16 \times \dfrac{9}{12} \times \dfrac{1}{100}=189 or x=1575$
P.W=Rs.1575
Sum of due =P.W +T.D =Rs.(1575+189)=Rs.1764
44064.A man wants to sell his scooter. There are two offers before him __ one at Rs 11000 cash and the other at Rs 13440 credit to be paid after 9 months , the rate of interest being 16% p.a. Which one is the better offer?
12,220
12,000
10,200
8,400
Explanation:
Present worth of Rs.13,440 due 9months
hence,$\dfrac{100 \times 13440}{100+16 \times \dfrac{9}{12}}$
=Rs.12,000
Clearly Rs.12,000 >Rs.11,000
Hence selling the scooter at Rs.13,440 credit is the better offer
Present worth of Rs.13,440 due 9months
hence,$\dfrac{100 \times 13440}{100+16 \times \dfrac{9}{12}}$
=Rs.12,000
Clearly Rs.12,000 >Rs.11,000
Hence selling the scooter at Rs.13,440 credit is the better offer
44279.If the true discount for a sum of ₹ 50000 for a period of 4 yr at a certain rate of interest per annum is ₹ 2000, find the rate of interest.
1%
1.5%
2%
5%
Explanation:
Given that, PW =₹ 50000,
TD =₹ 2000, T = 4 yr and R = ?
According to the formula, (1)
TD = (PW x R x T) / 100
⇒ 2000 = (50000 x R x 4) / 100
∴ R = (2000 x 100) / (50000 x 4) = 20/20 = 1%
Given that, PW =₹ 50000,
TD =₹ 2000, T = 4 yr and R = ?
According to the formula, (1)
TD = (PW x R x T) / 100
⇒ 2000 = (50000 x R x 4) / 100
∴ R = (2000 x 100) / (50000 x 4) = 20/20 = 1%