On 31st December, 2005 it was Saturday.
Number of odd days from the year 2006 to the year 2009 = (1 + 1 + 2 + 1) = 5 days.
On 31st December 2009, it was Thursday.
Thus, on 1st Jan, 2010 it is Friday.
The century divisible by 400 is a leap year.
$\therefore$ The year 700 is not a leap year.
Given that first day of a normal year was Friday
Odd days of the mentioned year = 1 [Since it is an ordinary year]
Hence First day of the next year = Friday + 1 Odd day = Saturday
Therefore, last day of the mentioned year = Friday
The year 2007 is an ordinary year. So, it has 1 odd day.
1st day of the year 2007 was Monday.
1st day of the year 2008 will be 1 day beyond Monday.
Hence, it will be Tuesday.
28 May, 2006 =2005 years + Period from 1.1.2006 to 28.5.2006
Odd days in 1600 years = 0
Odd days in 400 years = 0
5 years = 4 ordinary years + 1 leap year = 4 x 1 + 1 x 2 $\equiv$ 6 odd days
Clearly it can be understood from the question that 9 days ago was a Thursday
Number of odd days in 9 days = 2 [As 9-7 = 2, reduced perfect multiple of 7 from total days]
Hence today = Thursday + 2 odd days = Saturday
The year 2006 is an ordinary year. So, it has 1 odd day.
So, the day on 8th Dec, 2007 will be 1 day beyond the day on 8th Dec, 2006.
But, 8th Dec, 2007 is Saturday.
$\therefore$ 8th Dec, 2006 is Friday.
Given that 1st October is Sunday
Number of days in October = 31
31 days = 3 odd days
As we can reduce multiples of 7 from odd days which will not change anything
Hence 1st November = Sunday + 3 odd days = Wednesday
Given that seventh day of a month is three days earlier than Friday
=> Seventh day is Tuesday
=> 14th is Tuesday
=> 19th is Sunday
59 days = 8 weeks 3 days = 3 odd days
Hence if today is Thursday, After 59 days, it will be = Thursday + 3 odd days
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