Easy Tutorial
For Competitive Exams
Aptitude
TNPSC G4
10th CBSE Maths
  1. Home
  2. SSC CGL(Combined Graduate Level) Tier1 Test
  3. SSC CGL Tier1 Quantitative Aptitude

SSC CGL Tier1 Quantitative Aptitude Percentage Test 2

1291.In an examination, there are three papers and a candidate has to get 40% of the total to pass. In one paper he gets 62 out of 150 and in the second 35 out of 150. How much he get out of 180 in the third paper to qualify for a pass?
75
55
85
65
1292.The government has conducted a survey and which results 60% of the houses contained two or more people. Of those houses containing only one person 25% were having only a male. What is the percentageof all houses which contain exactly one female and no males?
95
105
10%
20%
1413.A student divided a number by 2/3 when he required to multiply by 3/2.
Calculate the percentage of error in his result.
2%
3%
0%
1%
Explanation:

Since 3x / 2 = x / (2 / 3)
2758.If A = x% of y and B = y% of x, then which of the following is true?
A is smaller than B.
A is greater than B
Relationship between A and B cannot be determined.
None of these
Explanation:

$ x $% of $ y $=$\left(\dfrac{x}{100}\times y \right)$=$\left(\dfrac{y}{100}\times x \right)$

2759.The population of a town increased from 1,75,000 to 2,62,500 in a decade. The average percent increase of population per year is:
4.37%
5%
6%
8.75%
Explanation:

Increase in 10 years = (262500 - 175000) = 87500.

Increase% =$ \left(\dfrac{875 00}{175000} \times 100\right) $% = 50%.

$\therefore$ Required average =$ \left(\dfrac{50}{10} \right) $% = 5%.

2761.How many litres of pure acid are there in 8 litres of a 20% solution?
2 litres
1.4 litres
1 litres
1.6 litres
Explanation:

Quantity of pure acid =8×$\dfrac{20}{100}$=1.6

2765.Two tailors X and Y are paid a total of Rs. 550 per week by their employer. If X is paid 120 percent of the sum paid to Y, how much is Y paid per week?
Rs. 200
Rs. 250
Rs. 300
None of these
Explanation:

Let the sum paid to Y per week be Rs. $ z $.

Then, $ z $ + 120% of $ z $ = 550.

$\Rightarrow z $ +$ \dfrac{120}{100} z $ = 550

$\Rightarrow \dfrac{11}{5} z $ = 550

$\Rightarrow z $ =$ \left(\dfrac{550 \times 5}{11} \right) $  = 250.

2767.A housewife saved Rs. 2.50 in buying an item on sale. If she spent Rs. 25 for the item, approximately how much percent she saved in the transaction ?
9%
10%
7%
6%
Explanation:

Actual price = Rs.25 + Rs.2.50 = Rs.27.5

Saving = Rs.2.5

Saving percent

=$\dfrac{2.5}{27.5}$×100=$\dfrac{250}{27.5}$=$\dfrac{2500}{275}$=$\dfrac{100}{11}$=9$\dfrac{1}{11}$% $\approx$ 9%

2768.A fruit seller had some apples. He sells 40% apples and still has 420 apples. Originally, he had:
588 apples
600 apples
672 apples
700 apples
Explanation:

Suppose originally he had $ x $ apples.

Then, (100 - 40)% of $ x $ = 420.

$\Rightarrow \dfrac{60}{100} \times x $ = 420

$\Rightarrow x $ =$ \left(\dfrac{420 \times 100}{60} \right) $  = 700.

2769.If 20% of a = b, then b% of 20 is the same as:
4% of a
5% of a
20% of a
None of these
Explanation:

$20$% of$ a=b \implies \dfrac{20}{100}a=b.$

$\therefore b$% of 20$=\left(\dfrac{b}{100}\times 20\right)=\left(\dfrac{20}{100}a \times \dfrac{1}{100}\times 20\right)=\dfrac{4}{100}a=4 $% of a$ $

Share with Friends