21856.The volume of 10 N and 4 N HCl required to make 1 litre of 7 N HCl are
0.75 litre of 10 N HCl and 0.25 litre of 4 N HCl
0.80 litre of 10 N HCl and 0.20 litre of 4 N HCl
0.60 litre of 10 N HCl and 0.40 litre of 4 N HCl
0.50 litre of 10 N HCl and 0.50 litre of 4 N HCl
21857.Which of the following set of variables give a straight line with a negative slope when plotted? (P = Vapour pressure; T = Temperature in K)
| y–axis | x–axis | |
|---|---|---|
| (1) | P | T |
| (2) | log10 P | 1/T |
| (3) | log10 P | T |
| (4) | log10 P | log10 1/T |
Option (1)
Option (2)
Option (3)
Option (4)
21858.The empirical formula of a nonelectrolyte is CH2O. A solution containing 3 g of the compound exerts the same osmotic pressure as that of 0.05 M glucose solution. The molecular formula of the compound is
C2H4O2
CH2O
C3H6O3
C4H8O4
21859.40% by weight solution will contain how much mass of the solute in 1 L solution, density of the solution is 1.2 g/mL?
480 g
48 g
38 g
380 g
21860.During osmosis, flow of water through a semipermeable membrane is
from both sides of semipermeable membrane with equal flow rates
from both sides of the semipermeable membrane with unequal flow rates
from solution having lower concentration only
from solution having higher concentration only
21861.Vapour pressure of pure ‘A’ is 70 mm of Hg at 25°C. It forms an ideal solution with ‘B’ in which mole fraction of A is 0.8. If the vapour pressure of the solution is 84 mm of Hg at 25°C, the vapour pressure of pure ‘B’ at 25°C is
56 m
70 mm
140 mm
28 mm
21862.When 20 g of naphthoic acid (C11H8O2) is dissolved in 50 g of benzene (Kf = 1.72 K kg mol–1) a freezing point depression of 2 K is observed. The Van’t Hoff factor ‘i’ is
0.5
1
2
3
21863.A 6% solution of urea is isotonic with
0.05 M solution of Glucose
6% solution of Glucose
25% solution of Glucose
1 M solution of glucose
21864.1.65 grams of HCl is dissolved in 16.2 grams of water. The mole fraction of HCl in the resulting solution is
0.4
0.3
0.2
0.1
21866.Which one is correct?
Molality changes with temperature
Molality does not change with temperature
Molarity does not change with temperature
Normality does not change with temperature
21867.When 25 grams of a non–volatile solute is dissolved in 100 grams of water, the vapour pressure is lowered by 2.25 × 10–1 mm. If the vapour pressure of water at 20°C is 17.5 mm, what is the molecular weight of the solute?
206
302
350
276
21868.Concentrated aqueous sulphuric acid is 98% H2SO4 by mass and has a density of 1.80 g mL–1. Volume of acid required to make one litre of 0.1 M H2SO4 is
5.55 mL
11.10 mL
16.65 mL
22.20 mL
21869.Which of the following can be measured by the Ostwald–Walker dynamic method?
Vapour pressure of the solvent
Relative lowering of vapour pressure
Lowering of vapour pressure
All of these
21870.One gram of silver gets distributed between 10 cm3 of molten zinc and 100 cm3 of molten lead at 800°C. The percentage of silver still left in the lead layer is approximately
5
2
1
3
21871.Two liquids X and Y form an ideal solution. At 300 K, vapour pressure of the solution containing 1 mole of X and 3 mole of Y is 550 mm Hg. At the same temperature, if 1 mole of Y is further added to this solution, vapour pressure (in mm Hg) ofX and Y in their pure states will be respectively
200 and 300
300 and 400
400 and 600
500 and 300
21872.The vapour pressure of water at 23°C is 19.8 mm. 0.1 mole of glucose is dissolved in 178.2 g of water. What is the vapour pressure (in mm) of the resultant solution?
19.0
19.602
19.402
19.202
21873.Equal volumes of 0.1 M and 0.2 M NaCl solutions are mixed. The concentration of nitrate ions in the resultant mixture will be
0.1 M
0.2 M
0.05 M
0.15 M
21874.The elevation in boiling point of a solution of 13.44 g of CuCl2 in 1 kg of water using following information will be (molecular wt. of CuCl2 = 134.4, Kb = 0.52 K molal–1)
0.16
0.05
0.1
0.2
21875.The freezing point (in °C) of a solution containing 0.1 g of K3[Fe(CN)6] (Mol. Wt. 329) in 100 g water (Kf = 1.86 K kg mol–1) is
–2.3 × 10–2
–5.7 × 10–2
–5.7 × 10–3
–1.2 × 10–2