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Verbal Reasoning Series Completion Prepare Q & A Page: 2
4499.7, 26, 63, 124, 215, 342, ?
391
421
481
511
Explanation:
The terms of the given series are (23 – 1), (33 – 1), (43 – 1), (53 – 1), (63 – 1), (73 – 1),…..So, missing term = (83 – 1) = (512 – 1) = 511.
4500.3, 12,27,48, 75, 108,?
147
162
183
192
Explanation:
The terms of the given series are 3 x l2, 3 x 22, 3 x 32, 3 x 42, 3 x 52, 3 x 62,…..So, missing term = 3 x 72 = 3 x 49 = 147.
4501.3, 7, 23, 95, ?
62
128
479
575
Explanation:
The pattern is x 2 + 1, x 3 + 2, x 4 + 3,…..So, missing term = 95 x 5 + 4 = 479.
4502.6, 18, 3, 21, 7, 56, ?
8
9
63
64
Explanation:
Each term at an even place in the series is the product of its two adjacent terms.Thus, if the missing term be x, then we have : 7 x x = 56 or x = 56 ÷ 7 = 8.
4503.4, 9, 25, ?, 121, 169, 289, 361
49
64
81
87
Explanation:
The given series consists of squares of consecutive prime numbersi.e. 22, 32, 52,…..,11, 132, 172, 192.
So, missing term = 72 = 49.
4504.6, 13,28,59,?
111
113
114
122
Explanation:

First term → 6
Second term → (6*2+1) = 13
Third term → (13*2+2) = 28
Fourth term → (28*2+3) = 59
Fifth term → (59*2+4) = 122

4505.4, 12, 36, 108, ?
144
216
304
324
Explanation:
The pattern is x 3.So, missing term = 108 x 3 = 324.
4506.Which term of the series 5, 8, 11, 14,…..is 320?
104th
105th
106th
64th
Explanation:
Clearly, 5 + 3 = 8, 8 + 3 = 11, 11 + 3 = 14, …..So, the series is an a.P. in which a – 5 and d = 3.Let 320 be the nth term of the series.
Then, 320 = 5 + (n – 1) x 3 or (n – 1) = 105 or n = 106.
4507.8, 9, 8, 7, 10, 9, 6, 11, 10, ?, 12
5
7
8
11
Explanation:
The given sequence is a combination of three series :I. 1st, 4th, 7th, 10th terms i.e. 8, 7, 6, ?II. 2nd, 5th, 8th, 11th terms i.e. 9, 10, 11, 12
III. 3rd, 6th, 9th terms i.e. 8, 9, 10 The pattern in I is – 1.
So, missing term = 6 – 1 = 5.
4508.3, 7, 15, ?, 63, 127
30
31
47
52
Explanation:
Each number in the series is one more than twice the preceding number.So, missing term = (15 x 2) + 1 = 31.
4509.121, 143, 165, 186, 209
143
165
186
209
Explanation:
Each term in the series is obtained by adding 22 to the preceding term.So, 186 is wrong and must be replaced by (165 + 22) i.e. 187.
4510.6, 15, 35, 77, 165, 221
35
77
165
15
Explanation:
The terms of the series are products of two consecutive prime numbers i.e. (2 x 3),(3 x 5), (5 x 7), (7 x 11),…..
So, 165 is wrong and must be replaced by (11 x 13) i.e. 143.
4511.8, 13, 21, 32, 47, 63, 83
13
21
32
47
Explanation:
The correct pattern is + 5, + 8, + 11, + 14,…..So, 47 is wrong and must be replaced by (32 + 14) i.e. 46.
4512.1, 2, 4, 8, 16, 32, 64, 96
4
32
64
96
Explanation:
Each term of the series is obtained by multiplying the preceding term by 2.So, 96 is wrong and must be replaced by (64 x 2) i.e. 128.
4513.3, 4, 10, 32, 136, 685, 4116
10
32
136
4116
Explanation:
The correct pattern is x 1 + 1, x 2 + 2, x 3 + 3, x 4 + 4,…..So, 32 is wrong and must be replaced by (10 x 3 + 3) i.e. 33.
4514.105, 85, 60, 30, 0, – 45, – 90
105
60
0
-45
Explanation:
The correct pattern is – 20, – 25, – 30,…..So, 0 is wrong and must be replaced by (30 – 35) i.e. – 5.
4515.2, 5, 10, 17, 26, 37, 50, 64
17
26
37
64
Explanation:
The terms of the series are (12 + 1), (22 + 1), (32 + 1), (42 + 1), (52 + 1), (62 + 1),(72+1),…..
So, 64 is wrong and must be replaced by (82 + 1) i.e. 65.
4516.125, 126, 124, 127, 123, 129
126
124
123
129
Explanation:
The correct pattern is + 1, – 2, + 3, – 4, + 5.So, 129 is wrong and must be replaced by (123 + 5) i.e. 128.
4517.2, 5, 10, 50, 500, 5000
5
10
50
5000
Explanation:
Each term of the series is the product of the preceding two terms.So, 5000 is wrong and must be replaced by (50 x 500) i.e. 25000.
4518.1,3,12,25,48
3
12
25
48
Explanation:
The terms of the series are (l2 – 02), (22 – l2), (42 – 22), (62 – 32) and (82 – 42).So, 25 is wrong and must be replaced by (62 – 32) i.e. 27.
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