Easy Tutorial
For Competitive Exams

Volume occupied by single CsCl ion pair in a crystal is 7.014 × 10–23 cm3. The smallest Cs – Cs internuclear distance is equal to length of the side of the cube corresponding to volume of one CsCl ion pair. The smallest Cs to Cs internuclear distance is nearly

4.4 Å
4.3 Å
4 Å
4.5 Å
Additional Questions

The white ZnO turns yellow on heating because of

Answer

The crystal with metal deficiency defect is

Answer

A metal has a fcc lattice. The edge length of the unit cell is 404 pm. The density of the metal is 2.72 g cm–3. The molar mass ofthe metal is (NA = Avogadro's constant = 6.02 × 1023 mol–1)

Answer

The ionic radii of Rb+ and I are 1.46 Å and 2.16 Å respectively. The most probable type of structure exhibited by it is

Answer

The number of atoms per unit cell of bcc structure is

Answer

The number of hexagonal faces that are present in truncated octahedron is

Answer

In a face–centered cubic lattice, a unit cell is shared equally by how many unit cells?

Answer

A compound is formed by elements A and B. This crystallizes in the cubic structure where A atoms are at the corners of the cube and B atoms are at the body centres. The simplest formula of the compound is

Answer

The crystal system of a compound with unit cell dimensions, a = 0.387, b = 0.387 and c = 0.504 nm and α = β = 90° and γ = 120° is

Answer

The radius ratio in CsCl is 0.93. The expected lattice structure is

Answer
Share with Friends
Privacy Copyright Contact Us