A ladder 10 m long just reaches the top of a wall and makes an angle of 60° with the wall.Find the distance of the foot of the ladder from the wall (√3=1.73)
4.32 m
17.3 m
5 m
8.65 m
Explanation:
Let BA be the ladder and AC be the wall as shown above.
Then the distance of the foot of the ladder from the wall = BC
Given that BA = 10 m , $\angle$BAC = 60°
sin 60°=$\dfrac{BC}{BA}$
$\dfrac{\sqrt{3}}{2}=\dfrac{BC}{10}$
BC = 10×$\dfrac{\sqrt{3}}{2}$
=5×1.73
=8.65 m
Let BA be the ladder and AC be the wall as shown above.
Then the distance of the foot of the ladder from the wall = BC
Given that BA = 10 m , $\angle$BAC = 60°
sin 60°=$\dfrac{BC}{BA}$
$\dfrac{\sqrt{3}}{2}=\dfrac{BC}{10}$
BC = 10×$\dfrac{\sqrt{3}}{2}$
=5×1.73
=8.65 m