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The volume (V) of a monatomic gas varies with its temperature (T), as shown in the graph. The ratio of work done by the gas, to the heat absorbed by it, when it undergoes a change from state A to state B, is

$\dfrac{1}{3}$
$\dfrac{2}{3}$
$\dfrac{2}{5}$
$\dfrac{2}{7}$
Explanation:

Given process is isobaric
dQ n $C_{p}$ dT
dQ n $\left(\dfrac{5}{2}R\right)$ dT
dW = P dV = n RdT
Required ratio = $\dfrac{dW}{d Q}= \dfrac{nRdT}{n\left(\dfrac{5}{2}R\right)dT}= \dfrac{2}{5}$

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