A can copy 50 papers in 10 hrs., while A & B can copy 70 papers in 10 hrs.
It means B can copy 20 papers in 10 hrs.
Then time taken by B to copy 26 papers = 26 $\times$ 10/20 = 13 hours.
Total distance travelled = 24 $\times$ (20+5) = 600 kms
distance travelled by bus = 20 $\times$ 20=400 kms
distance travelled by train = 600-400=200kms
Average speed of train = 200/5=40 kmph.
Area of square = $x^2.$
Increment of length = 1.4x.
Increment of breadth = 1.3x
Area of rectangle = l×b = $1.82 x^2.$
Increment in area= $1.82 x^2$ - $x^2$= 82%.
Let total salary of the emp=30 $\times$ 4000=1,20,000
Now,
By adding one member that is Manager =31
So,
Total salary of the emp=31 $\times$ 4300=1,33,300
Net salary of the manager =1,33,300-1,20,000=13300.
Let the present age of A & B be 9x and 5x.
According to the condition,
=> 5x + 8 = 9x
=> 4x = 8.
=> x = 2.
Therefore, the present age of A = 9 $\times$ 2 = 18 and B = 5 $\times$ 2 = 10.
From the question,
$(4/7) ^3-(3/7) ^3$= $[(4^3) -(3^3)]/ (7^3)$
= $(64-27)/ (7^3)$
=37/343.
And,
$(4/7) ^2-(3/7) ^2$=$ [(4^2) -(3^2)]/ (7^2) $
= $[16-9]/ (7^2)$ =7/49.
Therefore, the required answer:
=> (37/343)/ (7/49) = (37 $\times$ 49/343)/7
=> (37/7)/7 = 37/49.
Let x be the average weight of 8 men (before replacement). Therefore (x+1.5) will be the average weight of 8 men (after replacement)
=> (7 $\times$ x + 68)/8 = x.
=> x = 65.
=> (7 $\times$ x + new)/8 = x + 1.5.
New = (8 $\times$ 65+8 $\times$ 1.5 × 8 $\times$ 65) = 65+12 = 77.
Let, the old radius be `r`.
New r=(100-10)/100= 0.9r.
Old area=3.14 $\times$ $r^2$
New area=3.14 $\times$ $0.81r^2$
Hence, % decrease= [3.14 $r^2$(1-0.81)] $\times$ 100/3.14 => $r^2$ = 19%.
If GERMANY is written as 7, 5, 18, 13, 1, 14, 25, how can FRANCE be written in that code?
Rohit walked 25 meters towards South. Then he turned to his left and walked 20 meters. He then turned to his left and walked 25 meters. He again turned to his right and walked 16 meters. At what distance is he from the starting point and in which direction?
A, B, C, D, E, F and G are sitting in a row facing North:
F is to the immediate right of E.
E is 4th to the right of G.
C is the neighbor of B and D.
Person who is third to the left of D is at one of ends. Who are to the left of C?
Their sitting arrangement is: - G B C D E F A.
Manju is the daughter of Anil. `Sheela is the mother of Manju. Therefore, Mohan is the son of Sheela.
Statements:
(I) `de fu la pane` means `rose flower is beautiful` and `la quiz` means `beautiful tree`.
(II) `de la chin` means `red rose flower` and `pa chin` means `red tea`.
From the two statements given in I, the code for the only common word `beautiful` can be determined.
From the two statements given in II, the code for the only common word `red` can be determined.
In I and II, the common words are `rose and `flower` and the common code words are `de` and `la`.
So, the code for `flower` is either `de` or `la`.
S1: A certain young man was entrusted to the care of a teacher.
P: This dullard will come to grief if I send him away without a single lesson, thought the teacher.
Q: He was so dull of the mind that he could not, even in three months time, learn as much as a single lesson.
R: The young man came to ask the teacher`s permission to go home.
S: It`s my business to provide a good education to my pupils to get on in life.
S6: The teacher asked him to wait.
Suppose the boy got x sums right and 2x sums wrong. Then, x + 2x = 48 3x = 48 x = 16.
| Today | = | Friday |
| Tomorrow | = | Saturday |
| Day After Tomorrow | = | Sunday |
| Before Sunday | = | Saturday |
| Two days after the day | = | Monday |
Assume there are x participants in the race. In a round race, number of participants in front of a person wil be x-1 and that behind him wil be x-1. i.e, 1/3(x-1) + 3/4(x-1) = x solving x = 13
X X X X
Y Y Y Y
Z Z Z Z
................
Y X X X Z
Required number = (L.C.M. of 12,16, 18, 21, 28) + 7 = 1008 + 7 = 1015