In order to have a hand shake there must be two members. Therefore to select 2 out of 12 we have 12C2.
This happens twice that is before and after the meeting
Answer = 12C2 × 2 = 132.
Going trip time = t = dsds = 1050 × 601050 × 60 = 12 minutes.
Given total time = 20 minutes
Return trip time = Total time - Going trip time = 20 - 12 = 8 minutes = 860860 hours.
As the distance is 10 miles during even return trip,
The return speed = dtdt = 1086010860 = 10 × 60810 × 608 = 75 mph.
Given that
Mary and John take 24 days; i.e., (Mary + John)`s 1 day`s work = 124124
John and Vino take 30 days; i.e., (John + Vino)`s 1 day`s work = 130130
Vino and Mary take 40 days; i.e., (Vino + Mary)`s 1 day`s work = 140140
Adding above 3 equations, we get,
[(Mary + John) + (John + Vino) + (John + Vino)]`s 1 day`s work = 124+130+140124+130+140
2((Mary + John + Vino)`s 1 days work = 124+130+140124+130+140
2(Mary + John + Vino)`s 1 days work = 5+4+31205+4+3120 = 110110
Therefore, (Mary + John + Vino)`s 1 days work = 120120
i.e., Mary, John and Vino together can complete the work in 20 days.
Let buying price of Ist stamp be Rs.x
Then
8000 - 0.2x = x
x = 8000/1.2
x = Rs.6666.67
Let buying price for IInd stamp be Rs.Y
Then
8000+0.2x = y
y = 8000/0.8
Y = Rs. 10000
Total money spend on purchasing the stamps
= x+y
= 6666.67+10000
= Rs.16666.67
Total money earned by selling the stamps = Rs.8000+8000
= Rs. 16000
Loss = Buying price - selling price
= Rs. 16666.67-16000
= Rs. 666.67 (Answer)
Formula for sum of n terms in AP = SnSn = n2(2a + (n - 1)d ]
5n + 4 => 5(n - 1) + 9 => [2(92)+(n-1)5][2(92)+(n-1)5]
Common difference (d) = 5, First term (a) = 9292
Similarly
Second series given 9n + 6 =>=> 9(n - 1) + 15 ? [2(152)+(n-1)9][2(152)+(n-1)9]
Common difference (d) = 9, First term (a) = 152152
So
13th term for first series is = a + 12d = 12921292
13th terms for second series is = a + 12d = 23122312
Ratio = 129231
Let the capacity of an engineer in P = x units, and in Q = y units.
Working capacity of P = x × 32 × 20
Working capacity of Q = y × 16 × 30
As the total work is same, we equate the above equations.
=> x × 32 × 20 = y × 16 × 30
=> xy = 16 × 30 × 32 × 20 = 34
Let the Salary be 100.
Salary was reduced by 25%. So present salary = 75.
Percentage has to be increased in order to get Original level = 2575 × 1002575 × 100 = 33.33 %
Let us take 100x kgs of ore. Now it contains 25x kgs of alloy and it contains 90% (25x) kgs of iron.
90% (25x) = 60 kg => x = 60 × 10090 × 12560 × 10090 × 125 = 8383
So iron ore required = 100 × 8383 = 266.66
Split the year 1775 + 16th july 1776
Till 1600 years no odd days.
1601 to 1700 = 5 odd days
1701 to 1775 = 75 + 18 = 93 = 2 odd days. (75 years has 93 odd days (=> 18 leap + 57 non leap years)
upto 15th july 1776 = 31 + 29 + 31 + 30 + 31 + 30 + 15 = 197 = 1 odd day.
Total odd days = 5 + 2 + 1 = 8 = 1 odd day.
So one day after Monday. That is Tuesday.
Take radius 100. Then surface area is 4 × pp × 100 × 100.
After increase radius by 50% the radius becomes100 + 50% of 100 = 150
Then new surface area is 4 × $\pi^2$ × 150 × 150
Then put the values into formula of percentage = 4$\pi$1502 - 4$\pi$10024$\pi$1002 × 1004$\pi$1502 -4$\pi$10024$\pi$1002 × 100 = 125%
8th Dec 2007 - 8th Dec 2006 = 52 weeks 1 day. So Dec 8th 2006 is behind one day = Friday.
Mitigate means to make something less severe. Divulge means reveal. Denote means indicate. Diminish means to make or to cause something to become less in size, importance etc.
Let the price be = Rs.100, and number of units sold = 100
Then, sale value = Rs.(100 × 100) = Rs.10000
New sale value = Rs.(130 × 80) = Rs.10400
Increase% = 4001000040010000 × 100 = 4%
Formula n(a?b) = n(a) + n(b) - n(anb)
Fail in Hindi or English = 35 + 45 - 20 = 60
Therefore students who passed = 100 - 60 = 40.
Answer: 100 degrees
Let the capacity of man = 3 units, and boy = 2 units per hour.
Now total work = 3 × 180 × 8 × 7 × 10 = 3 km. - - - - - - - (1)
Let k boys were recruited. Now total work = (3 × 180 + 2 × k) × 9 × 7 × 30 = 12km. - - - - - - (2)
By dividing 2nd equation by 1st,
=> (540+2k) × 9 × 7 × 303 × 180 × 8 × 7 × 10 = 4(540+2k) × 9 × 7 × 303 × 180 × 8 × 7 × 10 = 4
=> k = 50.
Let the total work = 30 units.
Then capacity of A = 3 units, B = 2 units. Now they worked for 5 days. So they must have completed 25 units.
Rest of the work 5 units done by C in 2 days. So C capacity = 5/2 = 2.5 units.
Given that toatal wages are Rs.1500 for 30 units. So for 1 unit of work they get Rs.50. Now B and C per day
work = (2 + 2.5) = 4.5 units. So their daily wages = 4.5 $\times$ 50 = Rs.225.
If each number is multiplied by K, then the new average increases by K times. So new average = 84
Let the number of correct answers be x.
Then numbers of incorrect answers will be 75 - x
We get 4x - (75 - x) × 1 = 125
On solving the equation we get x= 40.
For convert km/hr into m/sec multiply the speed with 518518
For convert m/sec into km/hr multiply the speed with 185185
80 × 518518 => 22 × 2929 m.sec.