41924.A two-digit number is such that the product of the digits is 8. When 18 is added to the number, then the digits are reversed. The number is:
18
24
42
81
Explanation:
Just go in reverse order.
Check the options with th subtracting 18 from each option for getting reverse number.
42 – 18 = 24 (which is in reverse).
So answer is 42.
Just go in reverse order.
Check the options with th subtracting 18 from each option for getting reverse number.
42 – 18 = 24 (which is in reverse).
So answer is 42.
41925.A man purchased a watch for Rs. 400 and sold it at a gain of 20% of the selling price. The selling price of the watch is ?
200
240
480
500
Explanation:
C.p. = Rs 400
Gain = 20%
S.P = C.P × $\dfrac{100+p%}{100}$ = 480
C.p. = Rs 400
Gain = 20%
S.P = C.P × $\dfrac{100+p%}{100}$ = 480
41926.The cost of two varieties of paint is Rs. 3969 per 2 kg and Rs. 1369 per 2 kg respectively. After how many years will the value of both paint be the same, if variety 1 appreciates at 26% per annum and variety 2 depreciates at 26% per annum ?
26
2
39
5
Explanation:
Simply appreciates variety 1 by 26% and depreciates variety 2 by 26% as:
3969(1-$\dfrac{1}{26}$)n = 1369(1 + $\dfrac{1}{26}$)n
For n = 2 we get both values equal.
So the price become same after 2 years.
Simply appreciates variety 1 by 26% and depreciates variety 2 by 26% as:
3969(1-$\dfrac{1}{26}$)n = 1369(1 + $\dfrac{1}{26}$)n
For n = 2 we get both values equal.
| Variety 2 | Variety1 | |
|---|---|---|
| 3969.00 | 1369 | Initially |
| 2937.06 | 1724.94 | after I year |
| 2173.42 | 2173.42 | after II year |
So the price become same after 2 years.
41927.An exhibition was conducted for 4 weeks. The number of tickets sold in 2nd week was increased by 20% and increased by 16% in the 3rd week but decreased by 20% in the 4th week. Find the number of tickets sold in the beginning, if 1392 tickets were sold in the last week ?
1250
2250
1300
1200
Explanation:
Let initially A tickets have been sold.
So now in 2nd week 20% increases so
A × $\dfrac{120}{100}$
In 3rd week 16% increases so
A × $\dfrac{120}{100}$× $\dfrac{116}{100}$umber.
Let initially A tickets have been sold.
So now in 2nd week 20% increases so
A × $\dfrac{120}{100}$
In 3rd week 16% increases so
A × $\dfrac{120}{100}$× $\dfrac{116}{100}$umber.
41928.In an exam, Ajith, Sachu, Karna, Saheep and Ramesh scored an average of 39 marks. Saheep scored 7 marks more than Ramesh. Ramesh scored 9 fewer than Ajith. Sachu scored as many as Saheep and Ramesh scored. Sachu and Karna scored 110 marks between them. If Ajith scores 32 marks then how many marks did Karna score?
57
50
60
55
Explanation:
Let marks of Ajith = a ; Sachu = sc ; Karna = k ; Saheep = sh and Ramesh = r then
sh – r = 7 - - - - (i)
a – r = 9 - - - - (ii)
sc = sh + r - - - - (iii)
sc + k = 110 - - - - (iv)
Also given a = 32
So from (ii) r = 23 and from (i) sh = 30 , from (iii) sc = 53, from (iv) k = 57.
Let marks of Ajith = a ; Sachu = sc ; Karna = k ; Saheep = sh and Ramesh = r then
sh – r = 7 - - - - (i)
a – r = 9 - - - - (ii)
sc = sh + r - - - - (iii)
sc + k = 110 - - - - (iv)
Also given a = 32
So from (ii) r = 23 and from (i) sh = 30 , from (iii) sc = 53, from (iv) k = 57.
41929.The average number of visitors of a library in the first 4 days of a week was 58. The average for the 2nd, 3rd, 4th and 5th days was 60. If the number of visitors on the 1st and 5th days were in the ratio 7:8 then what is the number of visitors on the 5th day of the library?
64
58
60
59
Explanation:
If number of visitors on 1st, 2nd, 3rd, 4th and 5th day are a, b, c, d and e respectively then
a + b + c + d = 58 × 4 = 232 - - - (i)
b + c + d + e = 60 × 4 = 240 - - - (ii)
Subtracting (i) from (ii), e – a = 8 - - - (iii)
Given that e : a = 8 : 7
Let e = 8x and a = 7x.
Given, 8x – 7x = 8 ⇒ x = 8 - - - (iv)
So a = 56 and e = 64.
If number of visitors on 1st, 2nd, 3rd, 4th and 5th day are a, b, c, d and e respectively then
a + b + c + d = 58 × 4 = 232 - - - (i)
b + c + d + e = 60 × 4 = 240 - - - (ii)
Subtracting (i) from (ii), e – a = 8 - - - (iii)
Given that e : a = 8 : 7
Let e = 8x and a = 7x.
Given, 8x – 7x = 8 ⇒ x = 8 - - - (iv)
So a = 56 and e = 64.
41930.A man said to a lady, "Your mothers husbands sister is my aunt". How is the lady related to the man.
Brother
Father
uncle
grandfather
Explanation:
Mothers husband is nothing but Father of the lady. So fathers sister will be Aunt to the Lady. But in question, they gave that, mothers husbands sister is Mans Aunt. So she is aunt to both the Lady and Man. So they should be brother and sister.
Mothers husband is nothing but Father of the lady. So fathers sister will be Aunt to the Lady. But in question, they gave that, mothers husbands sister is Mans Aunt. So she is aunt to both the Lady and Man. So they should be brother and sister.
41931.If a man reduces the selling price of a fan from 400 to 380 his loss increases by 20% .What is the cost price of fan ?
380
200
500
400
Explanation:
Let the cost price be x. Then initial loss = x - 400
Given that 20% ( x - 400) = 20
⇒ x - 400 = 100
⇒ x = 500
Let the cost price be x. Then initial loss = x - 400
Given that 20% ( x - 400) = 20
⇒ x - 400 = 100
⇒ x = 500
41932.260 can be represented as:
@****@**
@@*@@@@@@
@@*@@@@**
@*****@**
Explanation:
260 can be written in binary format as (100000100)2
Replacing 1 with @ and 0 with *, we get option d.
260 can be written in binary format as (100000100)2
Replacing 1 with @ and 0 with *, we get option d.
41933.A piece of ribbon 4 yards long is used to make bows requiring 15 inches of ribbon for each. What is the maximum number of bows that can be made?
8
9
10
11
Explanation:
1 yard = 3 feet = 3× 12 = 36 inches
4 yard = 4 × 36 = 144 inches
Number of maximum bows that can be made = $\dfrac{144}{15}$ = 9.6
Option B is correct.
1 yard = 3 feet = 3× 12 = 36 inches
4 yard = 4 × 36 = 144 inches
Number of maximum bows that can be made = $\dfrac{144}{15}$ = 9.6
Option B is correct.
41934.What is the next number of the following sequence
21,77,165,285,......
21,77,165,285,......
300
437
430
337
Explanation:
Look series
3 × 7 = 21
7 × 11 = 77
11 × 15 = 165
15 × 19 = 285
19 × 23 = 437 ans
T(n) = (4n – 1) × (4n + 3)
Put value of n find any term.
Look series
3 × 7 = 21
7 × 11 = 77
11 × 15 = 165
15 × 19 = 285
19 × 23 = 437 ans
T(n) = (4n – 1) × (4n + 3)
Put value of n find any term.
41935.A two-digit number is such that the product of the digits is 8. When 18 is added to the number, then the digits are reversed. The number is:
18
24
42
81
Explanation:
Just go in reverse order.
Check the options with th subtracting 18 from each option for getting reverse number.
42 – 18 = 24 (which is in reverse).
So answer is 24
Just go in reverse order.
Check the options with th subtracting 18 from each option for getting reverse number.
42 – 18 = 24 (which is in reverse).
So answer is 24
41936.Two guys work at some speed. After some time one guy realises he has done only half of the other guy completed which is equal to half of what is left So how much faster than the other is this guy supposed to do to finish with the first.
1time
2 times
3 times
5 times
Explanation:
If x is the part of task this is completed then,
1st has done work = (1 – x)/4 and 2nd has done work = (1– x)/2
So 2nd will have to increase his speed by 2 times.
If x is the part of task this is completed then,
1st has done work = (1 – x)/4 and 2nd has done work = (1– x)/2
So 2nd will have to increase his speed by 2 times.
41937.We are given 100 pieces of a puzzle. If fixing two components together is counted as 1 move ( a component can be one piece or an already fixed set of pieces), how many moves do we need to fix the entire puzzle.
88
99
97
90
Explanation:
Fixing 2 components together = 1 move
98 components are left ,to again fix one of these to the other two = 1 move
97 comp left,so 97 more moves
Total = 1 + 1 + 97 = 99.
Fixing 2 components together = 1 move
98 components are left ,to again fix one of these to the other two = 1 move
97 comp left,so 97 more moves
Total = 1 + 1 + 97 = 99.
41938.The ime a passenger train takes to cross another freight train is twice when the passenger train crosses the freight train running in opposite directions. What is the ratio of their speeds?
2 : 3
1 : 3
3 : 1
3 : 2
Explanation:
Speed of freight train = x
Speed of passenger train = y
Sum of their length = s
So time = s/(x – y)when both are in same direction
Time = s/(x + y) when opposite direction
From question s/(x – y) = 2.s/(x + y) so solving this we get, x/y = 3/1.
So x : y = 3 : 1
Speed of freight train = x
Speed of passenger train = y
Sum of their length = s
So time = s/(x – y)when both are in same direction
Time = s/(x + y) when opposite direction
From question s/(x – y) = 2.s/(x + y) so solving this we get, x/y = 3/1.
So x : y = 3 : 1
41939.At a recent birthday party there were four mothers and their children. Aged 1,2,3 and 4. from the clues below can you work out whose child is whose and their relevant ages?
It was janes childs birthday party.
Brian is not the oldest child.
Sarah had Anne just over a year ago.
Lauras Child will be next birthday.
Daniel is older than Charlie is.
Teresas child is the oldest.
Charlie is older than Lauras child.
It was janes childs birthday party.
Brian is not the oldest child.
Sarah had Anne just over a year ago.
Lauras Child will be next birthday.
Daniel is older than Charlie is.
Teresas child is the oldest.
Charlie is older than Lauras child.
charlies birthday party
Daniels birthday party
Brians birthday party
Annes birthday party
Explanation:
According to given points.
Anne is one yr old her mother is Sarah
Brian is 2 yr old his mom is Laura
Charlie is 3 yr old his mom is Jane
Daniel is 4 yr old his mom is Teresa.
And its charlies birthday party.
According to given points.
Anne is one yr old her mother is Sarah
Brian is 2 yr old his mom is Laura
Charlie is 3 yr old his mom is Jane
Daniel is 4 yr old his mom is Teresa.
And its charlies birthday party.
41940.Ajith was driving down the country side when he saw a farmer tending his pigs and ducks in his yard. Ajith asked the farmer how many of each he had. The farmer replied that there were 60 eyes and 86 feet between them. How many ducks and how many pigs were there ?
17
13
26
4
Explanation:
Let the no of ducks be x and no of pigs be y.
Then,since there are 60 eyes in total and both ducks and pigs have 2 eyes we have 2x + 2y = 60 - - - (1)
And total number of legs are 86, ducks have 2 legs while a pig has four so 2x + 4y = 86 - - - (2)
Subtracting (1) from (2) ,we get
2y = 26. ie. y = 13
Putting value in - - - (1),
We get x = 17
Let the no of ducks be x and no of pigs be y.
Then,since there are 60 eyes in total and both ducks and pigs have 2 eyes we have 2x + 2y = 60 - - - (1)
And total number of legs are 86, ducks have 2 legs while a pig has four so 2x + 4y = 86 - - - (2)
Subtracting (1) from (2) ,we get
2y = 26. ie. y = 13
Putting value in - - - (1),
We get x = 17
41941.A supportive young hare and tortoise raced in opposite directions around a circular track that was 100 yards in diameter. They started at the same spot, but the hare did not move until the tortoise had a start of one eighth of the distance ( that is, the circumference of the circle). The hare held such a poor opinion of the other’s racing ability that he sauntered along, nibbling the grass until he met the tortoise. At this point the hare had gone one sixth of the distance. How many times faster than he went before must the hare now run in order to win the race ?
more than 7 times
more than 8 times
more than 5 times
5 times
Explanation:
The hare and the tortoise are at the same point when hare have to cover 5/6 of the distance and tortoise have to cover 1/6 of the distance to complete the race.
If x is the speed of tortoise then itll take 1/(6 x) time to finish.
So, hare will have to run more then 5 times the speed of tortoise to win the race.
The hare and the tortoise are at the same point when hare have to cover 5/6 of the distance and tortoise have to cover 1/6 of the distance to complete the race.
If x is the speed of tortoise then itll take 1/(6 x) time to finish.
So, hare will have to run more then 5 times the speed of tortoise to win the race.
41942.Three times the first of three consecutive odd integers is 3 more than twice the third. The third integer is:
9
11
13
15
Explanation:
Let numbers are n,n + 2,n + 4
Now 3 n = 2(n + 4) + 3
3 n – 2 n = 11
So
N = 11 then consecutive odd numbers are 11, 13, 15
Let numbers are n,n + 2,n + 4
Now 3 n = 2(n + 4) + 3
3 n – 2 n = 11
So
N = 11 then consecutive odd numbers are 11, 13, 15
41943.A, B and C can do a piece of work in 20, 30 and 60 days respectively. In how many days can A do the work if he is assisted by B and C on every third day?
12 days
15 days
16 days
18 days
Explanation:
Work done in 3 days = (3/20) + (1/30) + (1/60) = 1/5
Remaining work = 4/5
If 1/5 work is done in 3 days then,
4/5 work is done in (3 × 5 × 4)/5 = 12 days
Total no. of days will become 12+3=15 days for the complete work to be done
Work done in 3 days = (3/20) + (1/30) + (1/60) = 1/5
Remaining work = 4/5
If 1/5 work is done in 3 days then,
4/5 work is done in (3 × 5 × 4)/5 = 12 days
Total no. of days will become 12+3=15 days for the complete work to be done