[System.out.println(new Ru...] Which constructs an anonymous inner class instance?

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TNPSC G4

10th CBSE Maths

Which constructs an anonymous inner class instance?

Runnable r = new Runnable() { };

Runnable r = new Runnable(public void run() { });

Runnable r = new Runnable { public void run(){}};

System.out.println(new Runnable() {public void run() { }});

Explanation:

D is correct. It defines an anonymous inner class instance, which also means it creates an instance of that new anonymous class at the same time. The anonymous class is an implementer of the Runnable interface, so it must override the run() method of Runnable.

Option A is incorrect because it doesnt override the run() method, so it violates the rules of interface implementation.

Option B and C use incorrect syntax.

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