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The geometry and magnetic behaviour of the complex $[Ni(CO)_4]$ are

Square planar geometry and paramagnetic
Tetrahedral geometry and diamagnetic
Square planar geometry and diamagnetic
Tetrahedral geometry and paramagnetic
Explanation:

$Ni(28) : [Ar]3d^8 4s^2$
∵CO is a strong field ligand
Configuration would be :

For, four ‘CO’-ligands hybridisation would be $sp^3$ and thus the complex would be diamagnetic and of tetrahedral geometry.

Additional Questions

Following solutions were prepared by mixing different volumes of NaOH and HCl of different concentrations :
a. $60 mL\dfrac{M}{10}HCL+40 mL\dfrac{M}{10} NaOH$
b. $55 mL\dfrac{M}{10}HCL+45 mL\dfrac{M}{10} NaOH$
c. $75 mL\dfrac{M}{5}HCL+25 mL\dfrac{M}{5} NaOH$
d. $100 mL\dfrac{M}{10}HCL+100 mL\dfrac{M}{10} NaOH$
pH of which one of them will be equal to 1?

Answer

On which of the following properties does the coagulating power of an ion depend?

Answer

Given van der Waals constant for $NH_3, H_2, O_2$ and $CO_2$ are respectively 4.17, 0.244, 1.36 and 3.59, which one of the following gases is most easily liquefied?

Answer

The solubility of $BaSO_4$ in water is 2.42 × $10^{–3} gL^{–1}$ at 298 K. The value of its solubility product $(K_{sp})$ will be
(Given molar mass of $BaSO_4 = 233 g mol–1)$

Answer

In which case is number of molecules of water maximum?

Answer

The correct difference between first and second order reactions is that

Answer

Among $CaH_2, BeH_2 , BaH_2,$ the order of ionic character is

Answer

Consider the change in oxidation state of Bromine corresponding to different emf values as shown in the diagram below :

Then the species undergoing disproportionation is

Answer

For the redox reaction
$MnO_4^-+C_2O_4^{2-}+H^+\rightarrow Mn^{2+} +CO_2 + H_2O$
The correct coefficients of the reactants for the balanced equation are
$MnO_4^-$ $C_2O_4^{2-}$ $H^+$

Answer

Which one of the following conditions will favour maximum formation of the product in the reaction,
$A_2(g)+B_2(g)\rightleftharpoons X_2(g)\triangle_r H=-XKJ?$

Answer
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