11391.The bankers gain on a sum due 3 years hence at 12% per annum is Rs. 270. The bankers discount is:
Rs. 960
Rs. 840
Rs. 1020
Rs. 760
11392.A man buys Rs. 20 shares paying 9% dividend. The man wants to have an interest of 12% on his money. The market value of each share is:
Rs. 12
Rs. 15
Rs. 18
Rs. 21
11393.A man standing at a point P is watching the top of a tower, which makes an angle of elevation of $30^\circ$ with the mans eye. The man walks some distance towards the tower to watch its top and the angle of the elevation becomes $60^\circ$. What is the distance between the base of the tower and the point P?
43 units
8 units
12 units
Data inadequate
11394.What is the difference between the compound interests on Rs. 5000 for 1 1/2 years at 4% per annum compounded yearly and half-yearly?
Rs. 2.04
Rs. 3.06
Rs. 4.80
Rs. 8.30
11395.Excluding stoppages, the speed of a bus is 54 kmph and including stoppages, it is 45 kmph. For how many minutes does the bus stop per hour?
9
10
12
20
11396.A sum fetched a total simple interest of Rs. 4016.25 at the rate of 9 p.c.p.a. in 5 years. What is the sum?
Rs. 4462.50
Rs. 8032.50
Rs. 8900
Rs. 8925
11397.The average of 20 numbers is zero. Of them, at the most, how many may be greater than zero?
0
1
10
19
42233.Look at this series: 2, 1, (1/2), (1/4), what number should come next?
1/3
1/8
2/8
1/16
Explanation:
1/2 in 2 = 1
1/2 in 1 = 1/2
1/2 in 1/2 = 1/4
1/2 in 1/4 = 1/8
1/2 in 2 = 1
1/2 in 1 = 1/2
1/2 in 1/2 = 1/4
1/2 in 1/4 = 1/8
42234.Look at this series: 36, 34, 30, 28, 24, … What number should come next?
20
22
23
26
Explanation:
This is an alternating number subtraction series.
First, 2 is subtracted, then 4, then 2, and so on.
Rule = (first number - 2) (second number - 4) (third number - 2) (fourth number - 4)......
Now The series is 36, 34, 30, 28, 24...
(36 - 2 = 34), (34 - 4 = 30), (30 - 2 = 28), (28 - 4 = 24), (24 - 2 = 22)...
So the answer is b = 22.
This is an alternating number subtraction series.
First, 2 is subtracted, then 4, then 2, and so on.
Rule = (first number - 2) (second number - 4) (third number - 2) (fourth number - 4)......
Now The series is 36, 34, 30, 28, 24...
(36 - 2 = 34), (34 - 4 = 30), (30 - 2 = 28), (28 - 4 = 24), (24 - 2 = 22)...
So the answer is b = 22.
42235.Look at this series: 22, 21, 23, 22, 24, 23, … What number should come next?
22
24
25
26
Explanation:
In this simple alternating subtraction and addition series;
1 is subtracted, then 2 is added, and so on.
Rule = (first number - 1) (second number + 2) (third number - 1) (fourth number + 2)......
Now The series is 22, 21, 23, 22, 24, 23, . . .
(22 - 1 = 21), (21 + 2 = 23), (23 - 1 = 22), (22 + 2 = 24), (24 - 1 = 23) (23 + 2 = 25)...
So the answer is c = 25.
In this simple alternating subtraction and addition series;
1 is subtracted, then 2 is added, and so on.
Rule = (first number - 1) (second number + 2) (third number - 1) (fourth number + 2)......
Now The series is 22, 21, 23, 22, 24, 23, . . .
(22 - 1 = 21), (21 + 2 = 23), (23 - 1 = 22), (22 + 2 = 24), (24 - 1 = 23) (23 + 2 = 25)...
So the answer is c = 25.
42236.Look at this series: 53, 53, 40, 40, 27, 27, … What number should come next?
12
14
27
53
Explanation:
In this series, each number is repeated, then 13 is subtracted to arrive at the next number.
Rule = (1st number) (1st number) (1st number - 13 = 2nd number) (2nd number repeat) (2nd - 13 = 3rd number) (3rd number repeat)....
The series is 53, 53, 40, 40, 27, 27...
(53),(53 - 13 = 40), (40), (40 - 13 = 27) (27), (27 - 13 = 14), (14)...
So the answer is b = 14.
In this series, each number is repeated, then 13 is subtracted to arrive at the next number.
Rule = (1st number) (1st number) (1st number - 13 = 2nd number) (2nd number repeat) (2nd - 13 = 3rd number) (3rd number repeat)....
The series is 53, 53, 40, 40, 27, 27...
(53),(53 - 13 = 40), (40), (40 - 13 = 27) (27), (27 - 13 = 14), (14)...
So the answer is b = 14.
42237.Look carefully for the pattern, and then choose which pair of numbers comes next. 28 25 5 21 18 5 14
11 5
10 7
11 8
5 10
Explanation:
This is an alternating subtraction series with the interpolation of a random number, 5, as every third number. In the subtraction series, 3 is subtracted, then 4, then 3, and so on.
This is an alternating subtraction series with the interpolation of a random number, 5, as every third number. In the subtraction series, 3 is subtracted, then 4, then 3, and so on.
42238.Look carefully for the pattern, and then choose which pair of numbers comes next, 42 40 38 35 33 31 28?
25 22
26 23
26 24
25 23
Explanation:
This is an alternating subtraction series in which 2 is subtracted twice, then 3 is subtracted once, then 2 is subtracted twice, and so on.
This is an alternating subtraction series in which 2 is subtracted twice, then 3 is subtracted once, then 2 is subtracted twice, and so on.
42239.A person crosses a 600 meter long street in 5 minutes. What is the speed in Km/hr
6.2 km/hr
7.2 km/hr
8.2 km/hr
9.2 km/hr
Explanation:
Two things to give attention on this question.
First time is in minutes, we need to change it to seconds to get speed in m/sec, then we need to get the final answer in km/hr.
So lets solve this.
Speed=Distance/Time
Distance=650meter
Time=5 minutes=300sec
Speed=600/300
=2m/sec
=>2∗18/5km/hr
=7.2km/hr
Two things to give attention on this question.
First time is in minutes, we need to change it to seconds to get speed in m/sec, then we need to get the final answer in km/hr.
So lets solve this.
Speed=Distance/Time
Distance=650meter
Time=5 minutes=300sec
Speed=600/300
=2m/sec
=>2∗18/5km/hr
=7.2km/hr
42240.If a person walks at 14 km/hr instead of 10 km/hr, he would have walked 20 km more. The actual distance travelled by him is:
50 km
56 km
70 km
80 km
Explanation:
Let the actual distance travelled be x km.
Then,$\dfrac{x}{10}=\dfrac{x+20}{14}$
14x = 10x + 200
4x = 200
x = 50 km.
Let the actual distance travelled be x km.
Then,$\dfrac{x}{10}=\dfrac{x+20}{14}$
14x = 10x + 200
4x = 200
x = 50 km.
42241.Excluding stoppages, the speed of a bus is 54 kmph and including stoppages, it is 45 kmph. For how many minutes does the bus stop per hour?
9
10
12
20
Explanation:
We are given that speed of the Bus with stoppage is 45km/hr. Which means the Bus actually travels 45 km in an hour. This does not mean the bus actually travelled for full 60 minutes, because it is given that the bus had stoppages.
Now the duration in an hour the bus actually travels, the speed of the bus during that duration is 54km/hr.
So lets say the bus actually travels for T minutes in an hour. From the given information we can say
54 * T/60 = 45
T = 45 *60/54 = 50 minutes.
So the duration of the stoppage in 1 hour = 60 - 50 = 10 mins.
Answer is B)10
We are given that speed of the Bus with stoppage is 45km/hr. Which means the Bus actually travels 45 km in an hour. This does not mean the bus actually travelled for full 60 minutes, because it is given that the bus had stoppages.
Now the duration in an hour the bus actually travels, the speed of the bus during that duration is 54km/hr.
So lets say the bus actually travels for T minutes in an hour. From the given information we can say
54 * T/60 = 45
T = 45 *60/54 = 50 minutes.
So the duration of the stoppage in 1 hour = 60 - 50 = 10 mins.
Answer is B)10
42242.In how many different ways can the letters of the word ‘LEADING’ be arranged in such a way that the vowels always come together?
360
480
720
5040
Explanation:
In the given word LEADING, there are 3 vowels - E, A & I & we want them together.
As this is a word with 7 letters, we can choose consecutive places in 5 ways.
3 vowels can change their places in 3! ways.
Other 4 consonants can reverse themselves in 4! ways.
Total ways = 5 × 3! × 4! = 720.
In the given word LEADING, there are 3 vowels - E, A & I & we want them together.
As this is a word with 7 letters, we can choose consecutive places in 5 ways.
3 vowels can change their places in 3! ways.
Other 4 consonants can reverse themselves in 4! ways.
Total ways = 5 × 3! × 4! = 720.
42243.Out of 7 consonants and 4 vowels, how many words of 3 consonants and 2 vowels can be formed?
210
1050
25200
21400
Explanation:
Number of ways of selecting (3 consonants out of 7) and (2 vowels out of 4) = (7C37C3*4C24C2)
= 210.
Number of groups, each having 3 consonants and 2 vowels = 210.
Each group contains 5 letters.
Number of ways of arranging 5 letters among themselves = 5! = 120
Required number of ways = (210 x 120) = 25200.
Number of ways of selecting (3 consonants out of 7) and (2 vowels out of 4) = (7C37C3*4C24C2)
= 210.
Number of groups, each having 3 consonants and 2 vowels = 210.
Each group contains 5 letters.
Number of ways of arranging 5 letters among themselves = 5! = 120
Required number of ways = (210 x 120) = 25200.
42244.A bank offers 5% compound interest calculated on half-yearly basis. A customer deposits Rs. 1600 each on 1st January and 1st July of a year. At the end of the year, the amount he would have gained by way of interest is:
120
121
122
123
Explanation:
Amount = Rs. $\left[ 1600 X \left( 1+\dfrac{5}{2 X 100} \right)^{2} \left( 1+\dfrac{5}{2 X 100} \right) \right]$
= Rs. $\left[ 1600 X \dfrac{41}{40} X \dfrac{41}{40} +1600 X \dfrac{41}{40} \right]$
= Rs. $\left[ 1600 X \dfrac{41}{40} \left( \dfrac{41}{40} + 1\right) \right]$
= Rs. $\left[\dfrac{1600X41X81}{40X40} \right]$
= Rs. 3321.
C.I. = Rs. (3321 - 3200) = Rs. 121
Amount = Rs. $\left[ 1600 X \left( 1+\dfrac{5}{2 X 100} \right)^{2} \left( 1+\dfrac{5}{2 X 100} \right) \right]$
= Rs. $\left[ 1600 X \dfrac{41}{40} X \dfrac{41}{40} +1600 X \dfrac{41}{40} \right]$
= Rs. $\left[ 1600 X \dfrac{41}{40} \left( \dfrac{41}{40} + 1\right) \right]$
= Rs. $\left[\dfrac{1600X41X81}{40X40} \right]$
= Rs. 3321.
C.I. = Rs. (3321 - 3200) = Rs. 121