Match the metal ions given in Column I with the spin magnetic moments of the ions given in Column II and assign the correct code :
| Column I | Column II |
|---|---|
| a. $Co^{3+}$ | i. $\sqrt{8}BM$ |
| b. $Cr^{3+}$ | ii. $\sqrt{35}BM$ |
| c. $Fe^{3+}$ | iii. $\sqrt{3}BM$ |
| d. $Ni^{2+}$ | iv. $sqrt{24}BM$ |
| v. $sqrt{15}BM$ |
a b c d
iv i ii iii
i ii iii iv
iv v ii i
iii v i ii
Explanation:
$Co^{3+} = [Ar] 3d^6, Unpaired e^–(n) = 4$
Spin magnetic moment = $\sqrt{4(4 +2)}=\sqrt{24} BM$
$\left[Ar\right]3d^3$, Unpaired e^–(n) = 3
Spin magnetic moment = $\sqrt{3(3 +2)}=\sqrt{15} BM$
$Fe^{3+}=\left[Ar\right]3d^5,$ Unpaired $e^{-}(n)=5$
Spin magnetic moment =$\sqrt{5(5 +2)}=\sqrt{35} BM$
$Ni^{2+} = [Ar] 3d^8,$ Unpaired $e^{-}(n)=2$
$\sqrt{2(2 +2)}=\sqrt{8}BM$
$Co^{3+} = [Ar] 3d^6, Unpaired e^–(n) = 4$
Spin magnetic moment = $\sqrt{4(4 +2)}=\sqrt{24} BM$
$\left[Ar\right]3d^3$, Unpaired e^–(n) = 3
Spin magnetic moment = $\sqrt{3(3 +2)}=\sqrt{15} BM$
$Fe^{3+}=\left[Ar\right]3d^5,$ Unpaired $e^{-}(n)=5$
Spin magnetic moment =$\sqrt{5(5 +2)}=\sqrt{35} BM$
$Ni^{2+} = [Ar] 3d^8,$ Unpaired $e^{-}(n)=2$
$\sqrt{2(2 +2)}=\sqrt{8}BM$